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Brake Doctor - Introduction, Disclaimer and Basic Hydraulics
Welcome
to the HEL Performance Brake Doctor. These pages are designed to
give you an overview of the braking system of your vehicle. Brake
hydraulics are a complex subject and the information contained
within the force and pressure, friction and piston travel pages
can be quite technical and hard to understand.
These
pages are offered as an introduction to the principles and parts
of the braking system. Reading this guide will not turn you into
an expert overnight. We have made every attempt to be accurate and
easy to read but we cannot impart the gifts of skill, experience
and common sense. If after reading these pages you feel inclined
to carry out alterations to the braking system of a bike we will
not accept responsibility for what happens next. You are
responsible for your own actions and these pages have been placed
online to only offer an introduction into the braking system and
to hopefully give you a greater background into how things work,
what effects changes may have and what different parts of the
system do. We will obviously be happy to answer any questions you
may have though via brakedoctor.
Brake Doctor - Brake System Hydraulics
The
most powerful part of your motorcycle is not the engine - it's the
brakes. That's a fact. Consider this - A GSXR1000 can do a
standing quarter mile in 10.8 seconds with a terminal speed of
138mph. Yet the brakes can do the same amount of work, but in
reverse, in just 6.8 seconds...
The
name hydraulics comes from the Greek word 'hydro' meaning
water and 'aulos' meaning pipe. The
basics of any hydraulic braking system are as follows. For a
hydraulic system to function it must be closed and completely full
of fluid and leak free – No fluid can be allowed to leave and no
air can be allowed to enter.
In
a closed, sealed hydraulic system as outlined above the following
laws are true
- Fluid
cannot be compressed to a lesser volume, no matter how high
the pressure
- Pressure
is equal over all surfaces of the containing system
The
things that concern us most with brake hydraulics are the
following :
-
Pressure
- Is a constant in the hydraulic system. If you put 10 psi
into a system hydraulic laws state that this 10 psi will act
on all surfaces within the system equally. Pressure In =
Pressure Out.
-
Force
- A 1 sq inch master cylinder with 10 lb of force applied to
it will produce 10 lb of force per square inch or 10 psi. If
the calipers have a surface area of 10 square inches then the
force here will be 10 x 10 lb which will mean the
calipers produce 100 lb of force. The pressure acting on the
system is the same, in this case 10 psi, but the force
can be altered by changing the surface area of the calipers.
-
Fluid
Displacement - If our 1 sq inch master cylinder travels
forward 1" then the amount of fluid it displaces will be
1 cubic inch. If this fluid is then spread over the 10 square
inches of caliper the calipers will only be able to move
1/10th of an inch. You will have huge force (100 lb) but the
caliper pistons may not move forward enough to grip the disc
tightly and so give a weaker brake. This can be seen to happen
on some motorcycles which have a small master cylinder piston
and two pot calipers. If the two pots are exchanged for six
pot calipers then the surface area increases and the force
increases at the caliper BUT the small master cylinder only
moves a small amount of fluid which in turn equates to a
smaller movement of the caliper pistons.
-
Lever
Pivot Point - Any effort you apply with your hand
should push the pads against the disc. But your hand isn't
that strong. To make the point grab hold of something and
squeeze it really hard - do you think that's enough pressure
to stop 270kgs of bike and rider from 180mph? Initially the
brake lever itself gives you an advantage by multiplying the
force at your hand through the lever. For instance, the
distance from the lever pivot point to the middle of the lever
(where your fingers are) might be 130mm. And yet the distance
from the pivot point to the point where the lever acts on the
master cylinder might only be 20mm. So, roughly speaking any
force applied to the lever will be 6.5 times greater at the
master cylinder (130mm/20mm = 6.5)
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